Compact Operators
We shall use the notion of sequential compactness in a separable Hilbert space. An example would be the closed unit ball
Compact Operator
Suppose
and are normed spaces. An operator is compact if all bounded sequences in have a subsequence such that converges in . Equivalently, is compact if the closure of the image of the unit ball in under is compact in .
e.g.
is compact if (i.e. dimension of the image) is finite. - Hilbert-Schmidt operators are compact. (See the corollary)
Proposition
Composition of a compact operator of bounded operator is compact.
Theorem
Suppose
is a bounded linear operator on Hilbert space , then
- If
is a compact operator on , then and are also compact. - If
is a family of compact linear operators with as tends to infinity, then is compact. - Conversely, if
is compact, there is a sequence of operators of finite rank such that . is compact if and only if is compact.
Corollary
Every Hilbert-Schmidt operator is compact.
Spectral Theorem
Lemma
Suppose
is a bounded self-adjoint linear operator on a Hilbert space . Then any eigenvalue of is real, and if and are eigenvectors corresponding to two distinct eigenvalues, then and are orthogonal.
Spectral Theorem of Compact Operators
Suppose
is a compact self-adjoint operator on a separable Hilbert space . Then there exits an orthonormal basis of , that consists of eigenvectors of . Moreover, if then and as . Conversely, every operator of the above form is compact and self-adjoint. The collection is called the spectrum of .
The Trace Class Operators
Trace Class Operator
A bounded linear operator
on a separable Hilbert space is called a trace class operator if where the positive operator , and are the singular values of . In this case, the trace norm is defined as
Proposition
The products of Hilbert–Schmidt operators are trace class.