Proof Clear enough as '' is an equivalence relation.
Smooth Path Space
The smooth path space to some manifold at point , denoted is the set of all tangent curves based at modulo the equivalence relation of first order agreement: And we introduce the vector operations on by selecting a chart around , and define . Clearly is a bijection, and now we can define the vector space operations on by
Definition by Vectors in
Tangent Space
For we define to be the set of pairs where is a chart in the atlas for with , and is an element of , modulo the equivalence relation which identifies a pair with a pair if and only if maps to under the derivative of the transition map between the two charts:
We denote such an equivalence class by .
Remark
We think of a vector as being an ‘arrow’ telling us which way to move inside the manifold. This information on which way to move is encoded by viewing the motion through a chart , and seeing which way we move ‘downstairs’ in the chart (this corresponds to a vector in according to the usual notion of a velocity vector). The equivalence relation just removes the ambiguity of a choice of chart through which to follow the motion.
Definition
Definition by Smooth Functions
Derivation Space
Denote as the set of real smooth functions whose domain includes some open neighborhood of . A derivation at a point is a map satisfying for all and the two conditions:
And we define to be the set of all derivations at .
Derivations are directional derivatives
The archetypal example of a derivation is the directional derivative of a function along a curve: Given a smooth path with , we can define Indeed, all derivations are of this form.
Three Definitions of Tangent Space are Equivalent
There are isomorphisms between the three spaces , and .
Proof
Remark
These are three characterizations of the tangent space to a manifold at a point. From now on, we will use the notation to denote the tangent space at , and treat each vector in as whatever definition is most convenient.
Proposition
Suppose is a smooth -manifold. The tangent space has dimension for all .
Proof It suffices to show that the differential of a local chart is a linear isomorphism between and . We have The map is a bijection since the derivative of a diffeomorphism is an invertible linear map.
Standard Basis of Tangent Space
Now suppose the chart around is given. Then one can define an ordered basis for as derivations: where each partial derivative operator (at ) is defined as
Proof Since we know the tangent space has dimension , it suffices to check the linear independence of the above vectors. Suppose . That is, for every smooth function , we have We can choose so that is the coordinate function , and we get Thus for all , and the vectors are linearly independent.
The Differential of a Smooth Function
Differential
Let be a smooth function. Then we define the differential of at point to the linear function on given by In general, the differential of a smooth map between two manifolds at , written is defined as
For the tangent curve definition, .
For the chart definition, .
For the derivation definition, .
We shall check that the above is well-defined, and all three definitions are equivalent:
Tangent Bundle
Tangent Bundle
A tangent bundle is the disjoint union of the tangent spaces of a manifold :
e.g. Consider , take the global chart . Then
Smooth Structure on Tangent Bundle
Given a smooth -manifold , with an atlas . Then has a canonical structure of dimension with its atlas given by
Proof The above construction gives a unique topology on such that the projection is continuous. Now we check the coordinate change is diffeomorphism. Consider is a composition of diffeomorphisms, thus a diffeomorphism.
Proof The bundle projection is the map defined by . Clearly . The local trivialization is given by the differential of the chart , say, It is easy to see that is a linear isomorphism onto .