Let be a metric space and . is called a limit point of if every open ball contains a point of other than .
Conversely, is called an isolated point of if there is an open ball that contains no elements of other than .
e.g.
Consider in with Euclidean metric. Then is an isolated point of , every point in is a limit point of and the closure of is .
Let be a metric space and . If is a limit point of , then every open ball contains infinitely many points of .
Proof
Theorem
if and only if every contains a point of .
Proof implies or is a limit point of . Thus every contains a point of . Suppose every contains a point of . If , then . If , then by the given condition, every contains a point of other than . Thus is a limit point of and hence .
Theorem
Let be a metric space and , then
Proof we haveTherefore . Consequently, This and imply . Since , we must have and thus .