FactImposing Relations
We interpret the quotient as imposing the relations or ‘killing’ the elements . Killing the elements in installments and in various orders, or in one strike lead to the same result. That is, we have following commutative diagram:
Adjoining Elements
A primary tool for constructing new rings is to take a ring and a ‘free’ variable and create the polynomial ring, and then quotient by a polynomial. We show see this further in field extensions by adjoining roots of polynomials.
e.g. The complex numbers are constructed from by setting . In fact, we can define . Clearly it is surjective and injective. Since $$ \begin{align}
\varphi(a+bi)\varphi(c+di)&=\overline{ac+(ad+bc)x+bdx^2} \
&=\overline{(ad+bc)x-bd+ac} \
&=\varphi((ad+bc)i+(ac-bd)) \
&=\varphi((a+bi)(c+di)),
\end{align} $$$\varphi$ is homomorphism, yielding a isomorphism.
Proposition
If in has no root in we can form the quotient and is a root of .
Definition
Whenever we have a subring of a ring and an element we denote by the smallest subring of that contains and .
Proposition
defines an isomorphism .
Field of Fractions & Product Rings
The Field of Fractions
Suppose is an integral domain. Consider equip with the following relation:
This is an equivalence relation. Let Missing argument for \frac\frac R denote the quotient. We denote the equivalence classes by .
Proposition
Missing argument for \frac\frac R is a field.
Theorem
Suppose is an integral domain and is defined as above. Define addition and multiplication on byThen is a field, denotes as . The map given by is an injective ring homomorphism.
e.g. If then . If , for a field , then the field of fraction of , denoted , is called the field of rational functions over :
DefProduct Rings
Let be rings. Then , with coordinate-wise addition and multiplication, is a ring with zero and identity element .
Prime and Maximal Ideals
Prime Ideal
Let be a ring. An ideal is prime if and implies that either or .
Theorem
Let be a ring. is prime if and only if is an integral domain.
Maximal Ideal
Let be a ring. An ideal is maximal if and there is no other ideal such that .
e.g. is maximal iff for a prime . In general, we have the following proposition holds:
Proposition
Let be a principle ideal domain, then is maximal if and only if is irreducible.
Proof In a PID, we have that iff . It follows that is maximal iff there is no proper divisor , which means is irreducible.
Corollary
If is a field, then is maximal iff is irreducible.