Positive Elements
Positive Element
An element
in a unital C*-algebra is said to be positive if it is self-adjoint and its spectrum consists of non-negative real numbers, i.e., . The set of all positive elements in is denoted by .
e.g. Let
Our main goal in this section is to show that the set of positive elements is precisely the set of elements of the form
Proposition
For any element
in a C*-algebra , is positive if and only if for some .
Proof We prove this in two steps.
- Step 1: We show that if
is a positive element, then must be zero. If , its spectrum is contained in . We also know that for any , the spectrum of is contained in . Since , the only way for both conditions to hold is if . Since is self-adjoint, its norm is equal to its spectral radius. Therefore, , which implies . By the C*-identity, , so . - Step 2: Let
. As is self-adjoint, we can decompose it into its positive and negative parts: , where and . Our goal is to show that . Consider the element . We compute : Substituting , we get: Since , we have , so the first term vanishes. Thus, . Since is positive, is also positive. We now have that is a positive element. By Step 1, this implies . If , then . Since is positive, implies . Therefore, , which means is a positive element.
Unique Positive Square Root
An element
is positive if and only if there exists a unique positive element such that . This element is called the positive square root of , denoted by .
Proof
- Existence: If
, then . The square root function is continuous on . By the continuous functional calculus, we can define . - Since
is a real-valued function, is self-adjoint. - The spectrum of
is , so . - By the properties of functional calculus,
. Since , we have .
- Since
- Uniqueness: Suppose there is another element
such that . Since is a polynomial in itself ( ), it commutes with . The element is a limit of polynomials in , so also commutes with . Now consider the commutative C*-algebra generated by and . By the Gelfand representation theorem, there is a -isomorphism for some compact Hausdorff space . We have and . Since , their Gelfand transforms and are non-negative real-valued functions. From , we can conclude that . Since the Gelfand map is an isomorphism, this implies .
Absolute Value and Positive/Negative Parts
For any self-adjoint element
, we define:
- The absolute value of
as . - The positive part of
as . - The negative part of
as . These elements are positive and satisfy
and .
The Partial Order on Self-Adjoint Elements
Lemma
If
, then .
Proof Since
The Partial Order on
Let
be the set of self-adjoint elements in . For , we write if . This defines a partial order on .
Ideals and Quotient Algebras
Ideals and Quotients of C*-Algebras
Let
be a closed two-sided ideal in a C*-algebra . Then:
is a self-adjoint ideal (i.e., a -ideal). - The quotient algebra
is a C*-algebra with the quotient norm.
To prove this, we first need a result about approximate identities.
Approximate Identity
For any
and , there exists an element with such that and . Such a family of elements is called an approximate identity for . If is an ideal, it contains an approximate identity for itself.
Proof of the Theorem
is a -ideal: We need to show that if , then . Since and is a right ideal, . Because is an ideal, it contains an approximate identity . These can be constructed via functional calculus on elements like , and since is closed, these elements lie in . We know that . Then, using the property that the involution is an isometry: So, . Each element is in because and . Since is the limit of a sequence of elements in and is a closed subspace, we must have . Thus, is a -ideal. is a C*-algebra: Since is a closed ideal in a Banach algebra , the quotient is a Banach algebra with the quotient norm . Since is a -ideal, is a Banach -algebra. We only need to verify the C*-identity: First, for any : Taking the infimum over all gives . For the reverse inequality, let be an approximate identity for . Then . We compute the square: Since , the element is in . Thus, .Therefore, for each : So, for all . Taking the limit as , we get: Combining the two inequalities, we obtain the C*-identity.